Convert Long to int?

[Peltito]

long myLong = 2;
int myInt = myLong.intValue();

Note: myLong.intValue() doesn't work because it says an object type is required but a long is found...? This function is straight out of the Long listing in the 1.3.1 api. What am I doing wrong? Thanks for the help!

[jamessan]

Originally posted by Peltito
long myLong = 2;
int myInt = myLong.intValue();long isn't a class. It's a primitive type. Long is a class. Notice the case difference. ;)

[MJPhill]

Did you try type casting?

long myLong = 2;
int myInt = (int)myLong;